Visual representation of adjacencies

eCAADe SIGraDi 2019 - Architecture in the Age of the 4th Industrial Revolution. (paper & talk)
W Lorenz, G. Wurzer. This paper is based on the assumption that a key challenge of good design is spatial organisation as a result of functional requirements. The authors present a new NetLogo application that assists designers to understand the proposed functional relationships (of spaces) by visualizing them graphically. ...

kleines Entwerfen customized bricks

digitales Entwerfen
G. Wurzer, W.E. Lorenz, S. Swoboda. Nach positiver Absolvierung der Lehrveranstaltung sind Studierende in der Lage algorithmisch zu Denken. Durch das Präzisieren der Problemstellung sind die Studierenden in der Lage den sinnvollen Einsatz von Algorithmen im Planungsprozess gedanklich zu erfassen. ...

Bridgemagazine Webpage

Webdesign für das bridgmagazin – Medieninhaber (Herausgeber) und Verleger: Österreichischer Bridgesportverband (ÖBV) | Audio Video Werbe-GmbH.

Stegreifentwerfen Hot Wood follow up

W.E. Lorenz, G. Wurzer, S. Swoboda. Nach positiver Absolvierung der Lehrveranstaltung sind Studierende in der Lage algorithmisch zu Denken. Konkret erlangen sie die Fähigkeit jene Teile des Entwurfsprozesses zu erkennen, die ausprogrammiert zu schnelleren und allenfalls besseren Lösungen führen. Dabei greifen die Studierenden auf die Ergebnisse des kleinen Entwerfens "Hot Wood" aus dem Sommersemester 2019 zurück. ...

4.2.2 Measured Dimension - Structured Walk Method

The measured dimension “d” is related to Mandelbrot's fractal dimension “D” by the equation D=1+d. The illustration on the left side displays a coastline, a mountain ridge or a border of a city on a specific scale, with the dotted line representing the border. The dimension of this curve can be calculated by using the structured walk method. Thereby the top of the line defines the starting point “0/0” from where the initial distance is marked on the curve. Where it hits the border, the distance is again marked on the curve and so on. When the end of the line or the starting point is reached, the total length for the specific is measured by using the equation , with being the total length and being the number of pieces of . Then the measurement is repeated by starting again at the point “0/0” but this time using which is half the size of .
After counting the pieces , the dimension of the border can finally be calculated as the comparison of both new polygons, see picture 24.

 picture 24: The measured dimensionIn the pictures below the coastline of Britain, taken from a map with a scale of 1:6.000.000, is replaced by five different polygons. The first one consists of seven 300 km straight-line segments which amount to a total length of 2289 km. This total length of the polygon increases by 232 km if the single polygon-line is reduced to 200 km. In the fourth picture 67.2 pieces of 50 km polygon-lines are required to enclose the coastline, which enlarge the total length to 3360 km. From this follows that the measured length of the polygons replacing the coastline increases when the scale, length of segments of the polygon, becomes smaller. Beside that as the straight-line segments are getting smaller and smaller, the polygon representing the coastline of Britain more and more approaches the shape on the map - which also means that the scale of the map, the exactness of the coastline, shows the limit for the size of the single straight-line segments. The replacing polygons are similar to the iterations of mathematical fractals, where the fractal curve is getting longer from one iteration to the next. The fractal dimension of the coastline indicates the increase in the length of the curve. What will happen to a Euclidean structure such as a circle if its length, respectively its circumference, is measured by replacing polygons - can we observe an increase of length, too? The equation for the circumference of a circle is , which amounts to 1256.63 units if we use a radius “R” of 200 units. The side of the polygon is calculated by the equation =2*R*sin(an/2). Defining , the angle of the first image, by 90 degrees this leads to =2*200*sin45=282.84 units. The circumference is again calculated by counting the pieces, in this case =4, and multiplying them by , which makes 1131 units. The length of the second polygon is given by =2*200*sin22.5=153.1 units which results in a total length of 1225 units. This shows that there is not much increase in length from the second , third - 1249 units -, fourth polygon - 1255 units - and finally to the calculated circumference of 1256 units.
 circle R=200units stage unit length "a" s "N" pieces length "L" dimension 1 s(1)= 282.8 1/283 N(1)= 4 1131 d D 2 s(2)= 153.1 1/153 N(2)= 8 1225 d(s1-s2)= 0.129 1.129 3 s(3)= 78.0 1/78 N(3)= 16 1249 d(s2-s3)= 0.029 1.029 4 s(4)= 39.2 1/39 N(4)= 32 1255 d(s3-s4)= 0.007 1.007 5 s(5)= 19.6 1/20 N(5)= 64 1256 d(s4-s5)= 0.002 1.002 D(slope)= 0.034 1.034 coastline stage unit length "a" s "N" pieces length "L" dimension 1 s(1)= 300 1/300 N(1)= 7.63 2289 d D 2 s(2)= 200 1/200 N(2)= 12.6 2521 d(s1-s2)= 0.239 1.239 3 s(3)= 100 1/100 N(3)= 29.1 2906 d(s2-s3)= 0.205 1.205 4 s(4)= 50 1/50 N(4)= 67.1 3360 d(s3-s4)= 0.209 1.209 5 s(5)= 25 1/25 N(5)= 165 4120 d(s4-s5)= 0.291 1.291 D(slope)= 0.231 1.231 Koch curve stage unit length "a" s "N" pieces length "L" dimension 1 s(1)= 333.3 1/333 N(1)= 4 1333 d D 2 s(2)= 111.1 1/111 N(2)= 16 1778 d(s1-s2)= 0.262 1.262 3 s(3)= 37.0 1/37 N(3)= 64 2370 d(s2-s3)= 0.262 1.262 4 s(4)= 12.3 1/12 N(4)= 256 3160 d(s3-s4)= 0.262 1.262 5 s(5)= 4.1 1/4 N(5)= 1024 4214 d(s4-s5)= 0.262 1.262 D(slope)= 0.262 1.262  =1st distance=1st scale; =1st length; = sum of -pieces; Generally spoken, the measured length increases when the scale decreases. If the value chosen for is too big, the measured dimension changes very much in relation to the measured dimension, for example between the scale of and . That means that the starting length of has to be chosen very carefully. Hausdorff-Besicovitch dimension: HB=log(N)/log(1/s)HB ... Hausdorff-Besicovitch dimensionN ... number of pieces by which the first line, initiator, is replaced1/s ... reduction factor, that is the length of the parts of the generator in relation to the initiator; For the Koch curve this results in: log(4)/log(3)=1.2618595;

Footnotes

 The smallest for natural structures also has to be choosen carefully because at one stage the scale of becomes as small as the scale of the image itself and no increase in length would be observed. This is then called the lower scale of the object.